Tell me what compiler did for me

[evehal]

fn main() {
    let s = String::from("sdf");
    let rs3:&str = &s;
    let rs:&String = &s;
}

so why i can get &str,&String from &String

[pcpthm]

This is the deref coercion.

[Yandros]

More precisely,

@https://doc.rust-lang.org/book/ch15-02-deref.html#how-deref-coercion-interacts-with-mutability

Rust does deref coercion when it finds types and trait implementations in three cases:

• From &T to &U when T : Deref<Target = U>

And for T = String and U = str, we do have String : Deref<Target = str>.

That's why let rs3: &str = &s; works: the compiler "inserts" an implicit .deref() / *_ on s: String:

let rs3: &str = &*s /* = s.deref() */;