Implicit `&Vec<T>` to `&[T]` conversion, but how?

help
1

Can someone explain, why a Vec<T> to &[T] works without boilerplate code?

fn main() {
    let v = vec![10, 20, 30];
    let f = first(&v); // why does this conversion from `Vec` to `&[]` work?
    
    println!("first of {v:?} is {f:?}");
}

fn first(slice: &[u32]) -> Option<u32> {
    slice.get(0).copied()
}
2

That's a Deref coercion, Treating Smart Pointers Like Regular References with the Deref Trait - The Rust Programming Language.

1 Like
3

oh thank you, didn't know that.

4

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