Less typing for struct in enum?

[Xav]

Hi,

using structs in an enum, is there a way to type less than what I currently do ?

pub(crate) struct Is_u16(u16);

pub(crate) struct Is_u32(u32);

pub(crate) enum Variant {
        t_u16(Is_u16),
        t_u32(Is_u32)
}

and later

let v = Variant::t_u16(Is_u16(5));

Not talking about the length of the name, or the name themselves, but rather something that avoids the ::t_u16(Is_u16(.

Thanks guys

[jofas]

Under the assumption that your newtype structs serve a purpose in your real code, I'd "hide" them in constructors of Variant so that your users don't need to explicitly wrap the integers when constructing Variant. I'd use From<u16> and From<u32> for that:

#![allow(non_camel_case_types)]

#[derive(Debug, PartialEq)]
pub(crate) struct Is_u16(u16);

#[derive(Debug, PartialEq)]
pub(crate) struct Is_u32(u32);

#[derive(Debug, PartialEq)]
pub(crate) enum Variant {
    t_u16(Is_u16),
    t_u32(Is_u32),
}

impl From<u16> for Variant {
    fn from(v: u16) -> Self {
        Self::t_u16(Is_u16(v))
    }
}

impl From<u32> for Variant {
    fn from(v: u32) -> Self {
        Self::t_u32(Is_u32(v))
    }
}

fn main() {
    let v16 = Variant::from(5u16);
    let v32 = Variant::from(5u32);

    assert_eq!(v16, Variant::t_u16(Is_u16(5)));
    assert_eq!(v32, Variant::t_u32(Is_u32(5)));
}

Playground.

That turns let v = Variant::t_u16(Is_u16(5)); into let v = Variant::from(5u16); which I think looks concise and quite pleasing.

[Xav]

Nice!

I will use your pattern instead.

thanks jofas