Why is the mutable reference copied?

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2

r2 is a reborrow of r1. you can use r1 again after the last use of r2.

for example, this is OK:

    let mut a: i32 = 0;
    let r1 = &mut a;

    let r2: &mut i32 = r1;

    println!("{}", r2);
    println!("{}", r1);

but this is NOT:

    let mut a: i32 = 0;
    let r1 = &mut a;

    let r2: &mut i32 = r1;

    println!("{}", r1);
    println!("{}", r2);

see also this recent thread:

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