let data: gpointer = ...
let gtk_socket: *mut gtk::ffi::GtkSocket = data as *mut _ as *mut gtk::ffi::GtkSocket;
I'm specifically referring to the
"as *mut _" part.
Why do we have to cast to "_" ???
To answer that you first need to know that
_ in Rust usually means "let the compiler infer the type".
With that in mind, something like
&mut u64 as *mut u64 means cast a a specific exclusive borrow type to a specific raw mutable pointer type.
The final step then is
&mut u64 as *mut _
&mut u64 as *mut u64.
This means essentially: cast the exclusive borrow to a raw mutable pointer to another type
T, but let the compiler infer what
T should be.
Hi and thanks, but:
I did know that the _ means let the compiler deduce the type, but my question is, perhaps, why do we have that step that is
"as *mut _" in that chain of casting, instead of just
data as *mut gtk::ffi::GtkSocket?
Because you can only cast from
&mut T to
*mut T while you can cast
*mut T to
*mut V for any
V (well, almost any
V). You can look at the rules here.
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