What does this line of code mean

```
let a = (0 != (3 & 3));
```

What does this line of code mean

```
let a = (0 != (3 & 3));
```

The `&`

operator performs a bitwise AND operation on both integers. Therefore `3 & 3`

is just a no-op generating `3`

since anything bitwise-ANDed with itself is just the same value, meaning the statement is equivalent to `let a = (0 != 3)`

which is just `let a = true;`

. Itβs a bit of a pointless line of code β maybe it makes more sense in context?

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thank you <3