Hi all.
I have a loop that iterates through some u8 values.
I want to push each value's HEX equivalent into a string but not sure how.
The code I have is as follows:
fn main() {
let mut signature_string = String::new(); //this is the variable I'd like to hold the result
let signature_code = [177,187,102,36,165,137,39,63,52,197,173,13,168,216,95,3,175,113,213,98,52,77,175,152,79,188,119,141,52,19,19,53,]; //in my program this is the array of u8 numbers
for a in signature_code().iter() {
println!(" N: {:x?}", a); //this prints the HEX version of the u8 but how do I get this into my string?
signature_string.push(a); //this fails and gives me the error below
}
println!("the entire array HEX as a single string: {}", signature_string);
}
The error I get is the following:
|
31 | signature_string.push(a);
| ^ expected char, found &u8
|
= note: expected type `char`
found type `&u8`
How can I convert each U8 value to it's HEX equivalent and push that value to a single string?
Thanks all!