This is probably a dumb question, but sometimes that's what I do. What's the expected output of this code?
fn main() {
for i in 250_u8 .. {
println!("{}", i);
}
}
Naively I expected it to scan and print the last values of an u8.
Thinking a second more about the semantics of ..
, I expect it to not print the last u8.
(So what can I do if I want the last u8 too? 250_u8..=
is not allowed for some reason. So I need the whole 250 ..= u8::MAX
for that, OK, and I am grateful of that because in past doing this was messier).
So I expect it to print up to the penultimate u8 value and then stop.
With a debug compilation I get a panic:
250
251
252
253
254
thread 'main' panicked at 'attempt to add with overflow', ...\src\libcore\ops\arith.rs:9
In an optimized build I get an infinite loop:
250
251
252
253
254
255
0
1
2
3
4
5
6
...
Is all this good?
If I have an array with all the u8s I can take and print the last items:
let data: [u8; 256] = [0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13,
14, 15, 16, 17, 18, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29,
30, 31, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45,
46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 60, 61,
62, 63, 64, 65, 66, 67, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77,
78, 79, 80, 81, 82, 83, 84, 85, 86, 87, 88, 89, 90, 91, 92, 93,
94, 95, 96, 97, 98, 99, 100, 101, 102, 103, 104, 105, 106, 107,
108, 109, 110, 111, 112, 113, 114, 115, 116, 117, 118, 119, 120,
121, 122, 123, 124, 125, 126, 127, 128, 129, 130, 131, 132, 133,
134, 135, 136, 137, 138, 139, 140, 141, 142, 143, 144, 145, 146,
147, 148, 149, 150, 151, 152, 153, 154, 155, 156, 157, 158, 159,
160, 161, 162, 163, 164, 165, 166, 167, 168, 169, 170, 171, 172,
173, 174, 175, 176, 177, 178, 179, 180, 181, 182, 183, 184, 185,
186, 187, 188, 189, 190, 191, 192, 193, 194, 195, 196, 197, 198,
199, 200, 201, 202, 203, 204, 205, 206, 207, 208, 209, 210, 211,
212, 213, 214, 215, 216, 217, 218, 219, 220, 221, 222, 223, 224,
225, 226, 227, 228, 229, 230, 231, 232, 233, 234, 235, 236, 237,
238, 239, 240, 241, 242, 243, 244, 245, 246, 247, 248, 249, 250,
251, 252, 253, 254, 255];
for x in &data[250 ..] {
println!("{}", x);
}
That's the (wrong) mental model I have used in the past for right-open intervals -.-