Nom ignore result of sub-combinator in `tuple()`

help
1

I have a lot of nom code that looks like this:

tuple((tag("let"), alpha1, tag("="), digit1))(input)

However, the result of tuple includes the values parsed for the let and = tokens, which is useless to me. So I have to use .map(|(input, (_, name, _, value)| ...) to filter it out. Is there a combinator, or some other way, to ignore the result of those combinators?

Based on the type signature of tuple, I'm guessing the answer is "no", but I figured I might as well ask, especially if I'm going about it the wrong way.

2

I would write that with the preceded() and separated_pair() combinators.
preceded(tag("let"), separated_pair(alpha1, tag("="), digit1))(input)

2 Likes
3

Just seeing this now, thank you! Those seem like exactly what I want. I guess I just need to use higher-level combinators.

4

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