Merge child process stdout and stderr

1

How do I merge child process stdout and stderr?

The following does not work (since ownership cannot be shared between stdout and stderr)...

let pipe = Stdio::piped();
let prog = Command::new("prog")
                        .stdout(pipe)
                        .stderr(pipe)
                        .spawn()
                        .expect("failed to execute prog");

So in other words what is the rust equivalent of 2>&1 on the shell?