Hi,
Since rust doesn't have a garbage collection, what would happens to the allocated memory when the variable holds that address and doesn't go out of scope?
For Example:
let mut five = Box::new(5); // LINE 1
five = Box::new(5); // LINE 2
What would happen to the allocated memory in LINE 1 when five doesn't go out of scope?? since five holds a new allocated memory.
The original value will be dropped when it is reassigned, so the LINE 1 box is freed on LINE 2.
@cuviper Thanks for the response. Is that same for value type? For example
let st = some_struct::new() // LINE 1; NOT BOXED - VALUE COPY
st = some_struct::new()
is that the same concept which is the original value will be dropped from memory?
Copy values can't have special implementations of Drop, so it's just overwritten. As a side note, your code wouldn't work because you didn't make the variable mutable.
Destructors always run when values are destroyed.
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