Laconic if enum is?

help
#1

Is there a way to write it laconically?

let ty_is_ref = if let syn::Type::Reference( _ ) = ty { true } else { false };

Is that the best way to write it?

#2 
let ty_is_ref = matches!(ty, syn::Type::Reference(_));
2 Likes
#3

Roger. Thank you @quinedot.

#4

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