This is something I find myself doing a lot. Is there a more succinct way to do this?
let variable = if let Some(variable) = variable {
variable
} else {
return;
};
I know I could do a macro, and sometimes I might opt for that, but is there another way I'm missing?
When the function returns a result or an option, I can use the ?
operator to do the unwrap, but what if the function returns ()
?
3 Likes
There's a new let else
feature coming soon which will let you write:
let Some(variable) = option else { return; }
10 Likes
Macro is the right way to do it. You can also wrap the code in an inner function:
fn outer() {
fn inner() -> Option<()> {
variable?;
Some(())
}
inner();
}
3 Likes
system
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4
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