Is there way to assign tuple returned by function to tuple in vector

help
1

See 'Is there a way to make this work?' in the following code:

#[derive(Copy, Clone, Eq, Hash, Debug, PartialEq)]
pub enum ChessPiece {
    WhiteKing,
    WhiteQueen,
    WhiteRook,
    WhiteKnight,
    WhiteBishop,
    WhitePawn,
    BlackKing,
    BlackQueen,
    BlackRook,
    BlackKnight,
    BlackBishop,
    BlackPawn,
    NoPiece,
}

pub fn get_clicked_square_id(x: f64, y: f64, scalar: f64) -> (f64, f64) {
    let board_width_height = 8f64;
    let range = 0f64..(scalar * board_width_height as f64);

    if !range.contains(&x) && range.contains(&y) {
        panic!("No Square ID")
    }
    (
        (x.div_euclid(scalar) * scalar),
        (y.div_euclid(scalar) * scalar),
    )
}

pub fn main() {

    let mut tuple_vec2: Vec<_> = vec![
        (29.0, 29.0, ChessPiece::WhiteRook, "a1"),
        (86.0, 0.0, ChessPiece::WhiteRook, "h1"),
    ];

    println!(
        "tuple_vec2[1].0 = {:?}, tuple_vec2[1].1 = {:?}",
        tuple_vec2[1].0, tuple_vec2[1].1
    );
    
    // ============================Is there a way to make this work in one line like this?
    (tuple_vec2[1].0, tuple_vec2[1].1) = get_clicked_square_id(100f64, 100f64, 57f64);
    // rather than
    let (x, y) = get_clicked_square_id(100f64, 100f64, 57f64);
    tuple_vec2[1].0 = x;
    tuple_vec2[1].1 = y;
    // ============================
    
    println!(
        "tuple_vec2[1].0 = {:?}, tuple_vec2[1].1 = {:?}",
        tuple_vec2[1].0, tuple_vec2[1].1
    );
}
2

No, there’s not a way to do that.

You might want to make a Position struct that has x and y members though which side steps the issue you’re having by having a single returned value from the function. As a benefit it makes the code a bit more clear about its intent.

3

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