Hi,
Is possible single line type definition in rust ?
for example:
my return type is haven't support &str but my next method needs str, so i must declare this like
let res: String = id;
uuid::Uuid::parse_str(&res).unwrap().simple().to_string()
Is available any solution to removing first line ?
something like this ?
uuid::Uuid::parse_str(&(res as String)).unwrap().simple().to_string()
You don't need the first line. The following should be fine:
uuid::Uuid::parse_str(&id).unwrap().simple().to_string()
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Origin (id) not have &str trait but it's have String, and destination just support &str.
if i use your code i will this error:
cannot infer type for
What is the type of id
? I assumed it was String
, but it sounds like that's not the case. Please provide a minimal example that shows your problem, if you can, ideally on the playground.
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Unfortunately playground could not support rusqlite library.
Id is a trait result. rusqlite::types::FromSql - Rust
Sorry when i uses your code, kind of error was different of cannot infer type for
I did attached my problem SC.
Try the following on line 65:
|r| r.get::<_, String>(0)
with all else the same.
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I want read more about ::<_, String>
what's name of this section in rust documents ?
The term to search would be "turbofish" - it's the way to explicitly state the type you want, when type inference cannot determine it (like in the case here). I now see why you had let res: String = id
- that informed type inference to use String
as well.
1 Like