I'm a little confused about this scene of loop and break

help
1 
fn main(){
    let mut counter = 0;
    let result = loop{
        counter +=1;
        if counter == 10{

            //Whether or not I add ";" here, the result will compile and pass and output 20
            break counter * 2;

        }
    };
    println!("{}",result);
}

The version I am using now is 1.79.0，I don't know why

2

break followed by an expression within a loop, in addition to terminating the loop, causes the loop block to evaluate to the given expression. I'd give an example code snippet demonstrating that, but it'd look almost exactly like yours.

3

If you put the ; it will be considered as a statement, while if you don't put the ; it will be considered as an expression. In this case there's no difference because both have the same effect of diverging and exiting the loop with the given value.

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4

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