I don't understand how Result<()> works

The Result<T, E>, takes two types T and E to work. But this example from the std lib broke my understanding. I mean if they used like Result<(), _>, I can get it the error type is inferred. But, how does this Result<()> work? What will be its error type?

The io::Result thing is a type alias that is defined like this:

type Result<T> = std::result::Result<T, std::io::Error>;

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