How to force rust to use already defined variable in tuple tuple destructuring

help
1 
 fn main() {
    let mut s1 = String::from("hello");

    let (s1, len) = calculate_length(s1);
    s1.push_str(" world"); // Error s1 is immutable

    println!("The length of '{}' is {}.", s1, len);
}

fn calculate_length(s: String) -> (String, usize) {
    let length = s.len(); // len() returns the length of a String
    (s, length)
}

how can I point to already defined s1 without having to create another mutable variable like this

let (mut s1, len) = calculate_length(s1);
2

Considered answer

Why are you passing String to calculate_length instead of just &str?

Direct answer

Like this:

fn main() {
    let mut s1 = String::from("hello");

    let len;
    (s1, len) = calculate_length(s1);
    s1.push_str(" world"); // Error s1 is immutable

    println!("The length of '{}' is {}.", s1, len);
}

fn calculate_length(s: String) -> (String, usize) {
    let length = s.len(); // len() returns the length of a String
    (s, length)
}

https://play.rust-lang.org/?version=stable&mode=debug&edition=2021&gist=c0652fa2e158f4c3e00685b7e5841113

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3

FYI, the code in the question seems to be adapted from the last example on this page of the Rust book.

It's used as a motivation for introducing the concept of borrowing on the next page. String slices and the suggestion to use &str in place of &String for function parameters come yet another page later.

2 Likes
4

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