Hi, in The Rust Book -> this section -> example 10-11

We have this code:

```
struct Point<X1, Y1> {
x: X1,
y: Y1,
}
impl<X1, Y1> Point<X1, Y1> {
fn mixup<X2, Y2>(self, other: Point<X2, Y2>) -> Point<X1, Y2> {
Point {
x: self.x,
y: other.y,
}
}
}
fn main() {
let p1 = Point { x: 5, y: 10.4 };
let p2 = Point { x: "Hello", y: 'c' };
let p3 = p1.mixup(p2);
println!("p3.x = {}, p3.y = {}", p3.x, p3.y);
}
```

Now i want to borrow `p1`

and `p2`

without moving them to the `mixup`

method, something like that (which will not compile):

```
struct Point<X1, Y1> {
x: X1,
y: Y1,
}
impl<X1, Y1> Point<X1, Y1> {
fn mixup<X2, Y2>(&self, other: &Point<X2, Y2>) -> Point<X1, Y2> {
Point {
x: self.x,
y: other.y,
}
}
}
fn main() {
let p1 = Point { x: 5, y: 10.4 };
let p2 = Point { x: "Hello", y: 'c' };
let p3 = p1.mixup(&p2);
println!("p3.x = {}, p3.y = {}", p3.x, p3.y);
}
```

Maybe i need a way to clone `self`

and `other`

inside `mixup`

to return a new `Point`

instance ...