I'm trying this in playground with error #[derive(Debug, Copy, Clone)] struct Foo<'a, T> { data: T, data2: &'a T, } impl<T:Copy> Foo<'_,T> { fn new(d: T) -> Self { Foo { data: d, data2: &d, } } …

Self-referential types are not possible in safe Rust. Split up your struct so that one type holds the data by value, while another one provides a borrowed view into it.

Alternatively, generate the reference on-the-fly when it's needed: struct Foo<T> { data: T } impl<T> Foo<T> { pub fn data2(&self)->&T { &self.data } }

Thank you. I think this should be allowed as the reference is immutable and ownership is with data var. For now I'll use the work around thank you everyone

Are you looking to keep the data field mutable? What makes generating a reference only when needed not ideal for your situation?

[image] insanebaba: I think this should be allowed as the reference is immutable and ownership is with data var. The problem is that Rust requires all types to be relocatable. Moving an object to another place in memory is always allowed by the object's owner, as long as the owner hasn't len…

How can I pass reference of data to self variable to another

help

admen February 19, 2021, 10:01am 3

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How can I pass reference of data to self variable to another

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