I want to embed an executable program in my app.
My question is whether I can run this app directly from memory without writing it to the disk and going through spawn?
So you have a chunk of memory which contains instructions in binary?
Just jump to it:
let func_addr = 0x8000;
let func: fn() = unsafe { std::mem::transmute(func_addr) };
func();
Needless to say, this is highly dangerous, but that's what the unsafe
is for
How about the command line arguments and stuff they arent exactly function arguments i believe
Oh, I see.
It's possible the easiest to extract it to the filesystem and then let the OS handle it.
I'm not entirely sure if you can load an ELF from memory. I highly doubt that
I see thanks for the answer
Isn't this likely to be complicated if the memory in question has been flagged as non-executable by the OS? How would you prevent this happening?
Well, it's... complicated.
TBH: The solution I gave is mainly focus on embedded devices, e.g. an updater which is loaded via UART and then jumped to.
If you have an OS, let the OS handle it.
There's a reason why execve
and friends only take paths to files, and not some memory chunks.
-<| Quoting Nikos Efthias via The Rust Programming Language Forum rust_lang+8eefbc752ac1c987ab7c384776f384b0@discoursemail.com, on Friday, 2019-10-18 08:25:10 AM |>-
I want to embed an executable program in my app.
My question is whether I can run this app directly from memory without writing it to the disk and going through spawn?
The libc
crate has definitions for fexecve(2)
,
shm_open(2)
, andSYS_memfd_create
(no wrapper). So the
primitives are there. You may have to copy the file though.
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