How can I do this work below in Rust?

help
1

As in Swift ,it's very convenient to do "print((1...100).reduce(0){$0 + $1})" ,calculate 1..100.

What about in Rust?

1 Like
2

Starting from Rust 1.12 (released today!), you can use the Iterator::sum method:

fn main() {
    // return type is required here, sum is quite generic
    println!("{}", (1..101).sum::<i32>());
}

More direct translation of your Swift code would use Iterator::fold instead:

fn main() {
    println!("{}", (1..101).fold(0, |a, b| a + b));
}

In either case, keep in mind that Rust's range is always exclusive at the end, hence 1..101.

3 Likes
3

And the many folks using the Nightly compiler can also write it with an inclusive syntax:

#![feature(inclusive_range_syntax)]

fn main() {
    println!("{}", (1 ... 100).sum::<u32>());
}
2 Likes
4

Actually starting from Rust 1.11. From today was the stabilization of Sum, the trait used to implement .sum().

5

wow,It's cool.