HashMap and HashBrown

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Is HashMap implementation in std based on HashBrown and thus there is no need to be explicitly importing that external crate?

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The hashmap in the standard library is hashbrown. So unless you need to use features only exposed by the crate (or new features not yet exposed in the std) you don't need the hashbrown crate.

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Thank you!

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(The implementation for std's HashMap wasn't always hashbrown and may be something else in the future, too. Part of the reason it's not just some re-export is for std to maintain the flexibility to change things in the future. Any API exposed in std must be maintained ~forever.)

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Sure, but I see this as a positive. One has "generic" API hidden under std::HashMap and if something changes under the hood one gets the goodies for free.

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