Erase ADC channel

[kossnikita]

Typically, working with a one shot ADC looks like this

    let mut adc = Adc::adc1(dp.ADC1);
    let sample = adc.read(&channel);
    print!("sample: {}", sample);

(Playground)

Is it possible to borrow the ADC channel to a structure to use like this

   let mut thermometer1 = MyAdcChannel::new(&mut pin1);
   let mut thermometer2 = MyAdcChannel::new(&mut pin2);

   let temp1 = thermometer1.read();
   let temp2 = thermometer2.read();

   print!("temperature1: {}, temperature2: {}", temp1, temp2);

Is it possible to do this with hal like stm32f4xx-hal? Or should erasing the ADC channel be implemented in hal?

I'm using rtic so I can pass the ADC in the shares, but I'd like to avoid this.

[kossnikita]

Was able to solve this problem similar to embedded-hal-bus

pub struct RefCellChannel<'a, T, ADC, Pin>
where
    T: OneShot<ADC, u16, Pin>,
    Pin: Channel<ADC>,
{
    adc: &'a RefCell<T>,
    pin: Pin,
    _adc: PhantomData<ADC>,
}

impl<'a, T, Pin, ADC> RefCellChannel<'a, T, ADC, Pin>
where
    T: OneShot<ADC, u16, Pin>,
    Pin: Channel<ADC>,
{
    /// Create a new `RefCellChannel`.
    #[inline]
    pub fn new(adc: &'a RefCell<T>, pin: Pin) -> Self {
        Self {
            adc,
            pin,
            _adc: PhantomData,
        }
    }

    pub fn read(&mut self) -> nb::Result<u16, <T as OneShot<ADC, u16, Pin>>::Error> {
        let adc = &mut *self.adc.borrow_mut();
        adc.read(&mut self.pin)
    }
}