Confusion about the add operate

why the i32 reference can add with i32

That works because there is an implementation of the Add trait between a i32 and &i32. The implementation is exactly as you would expect - first we dereference the &i32 to get a i32, then we add the two i32s together like normal.

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I think you linked the wrong implementation. It is actually this one.

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See also: Surprising: &1 + &1 == 2

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