Can only break with a value inside `loop` or breakable block

[ONiel]

Hello

I have a function which takes a string as a parameter. This parameter is the name of a cat. Now I want to return the cat from my vector of cats matching that name (assuming that all the cats have unique names).

This is a working solution:

    fn get(&mut self, name : String) -> Option<&Cat> {
        let mut seq = 0..self.cats.len();
        let mut cat : Option<&Cat> = None;
        for i in seq {
            if self.cats[i].name == name {
                cat = Some(&self.cats[i]);
                break;
            }
        }

        cat
    }

However, I'd like to know if there is a more elegant solution like this:

    fn get(&mut self, name : String) -> Option<&Cat> {
        for cat in &self.cats {
            if cat.name == name {
                break cat;
            }
        }

        None
    }

The second block of code is much shorter, cleaner, more intuitive, and easy to read.
However, it returns this error:

can only break with a value inside loop or breakable block

How can I fix this error so I can use the most elegant solution? Thanks! Or if there are other better options, let me now.

Thanks!

[asymmetrikon]

If you're returning the cat from the function, you can do

if cat.name == name {
    return Some(cat);
}

Though in this case, you can use Iterator::find:

fn get(&self, name: &str) -> Option<&Cat> {
    self.cats.iter().find(|c| c.name == name)
}