Calling methods on fallback integer type?

help
1

Why does the first code snippet fail with error error[E0599]: no method named abs found for type {integer} in the current scope:

let a = 3;
println!("{}", a.abs());

whereas, on specifying the type explicitly, this passes:

 let a = 3_i32;
 println!("{}", a.abs());

Isn't the default inferred type for numbers i32 as per this RFC? Then why are above two code snippets treated differently?

2

You are entirely correct. See Is not being able apply abs() without explicit types a limitation of type inference? for a discussion. The answer is "yes".

1 Like
3

Thanks for the pointer!

4

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