Best way to copy Option<&T>

1

What is the best way to write this function?

fn first(mut opt: Option<&mut String>) {
    match &mut opt {
        Some(v) => {
            second(Some(v));
        }
        None => {
            second(None);
        }
    }
    match &mut opt {
        Some(v) => {
            second(Some(v));
        }
        None => {
            second(None);
        }
    }
}
2 
fn first(mut opt: Option<&mut String>) {
    for _ in 0..2 {
        second(opt.as_deref_mut())
    }
}

Option::as_deref_mut lets you reborrow the Option<&mut String>, so that you don't move it within the loop. And the loop prevents code duplication.

Option has a ton of tiny useful functions like this, so it's super helpful to look through the docs for Option to see what's there.

3

Thank you. The loop is not applicable in my case, but as_dere_mut is what I was looking for.

4

Btw, if you click the pencil icon at the bottom right of your posts, you can edit your posts.

5

Yes, I know.